1-0.7b+0.05b^2=0

Solution for 1-0.7b+0.05b^2=0 equation:

1-0.7b+0.05b^2=0

a = 0.05; b = -0.7; c = +1;
Δ = b2-4ac
Δ = -0.72-4·0.05·1
Δ = 0.29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.7)-\sqrt{0.29}}{2*0.05}=\frac{0.7-\sqrt{0.29}}{0.1}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.7)+\sqrt{0.29}}{2*0.05}=\frac{0.7+\sqrt{0.29}}{0.1}
$